4y+35=56+y

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Solution for 4y+35=56+y equation: 



4y+35=56+y

We move all terms to the left:

4y+35-(56+y)=0

We add all the numbers together, and all the variables

4y-(y+56)+35=0

We get rid of parentheses

4y-y-56+35=0

We add all the numbers together, and all the variables

3y-21=0

We move all terms containing y to the left, all other terms to the right

3y=21

y=21/3

y=7

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