4y+3y+2=y-4

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Solution for 4y+3y+2=y-4 equation: 



4y+3y+2=y-4

We move all terms to the left:

4y+3y+2-(y-4)=0

We add all the numbers together, and all the variables

7y-(y-4)+2=0

We get rid of parentheses

7y-y+4+2=0

We add all the numbers together, and all the variables

6y+6=0

We move all terms containing y to the left, all other terms to the right

6y=-6

y=-6/6

y=-1

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