4y+4(y+3)=36

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Solution for 4y+4(y+3)=36 equation: 



4y+4(y+3)=36

We move all terms to the left:

4y+4(y+3)-(36)=0

We multiply parentheses

4y+4y+12-36=0

We add all the numbers together, and all the variables

8y-24=0

We move all terms containing y to the left, all other terms to the right

8y=24

y=24/8

y=3

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