4y+4+(3y-20)=180

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Solution for 4y+4+(3y-20)=180 equation: 



4y+4+(3y-20)=180

We move all terms to the left:

4y+4+(3y-20)-(180)=0

We add all the numbers together, and all the variables

4y+(3y-20)-176=0

We get rid of parentheses

4y+3y-20-176=0

We add all the numbers together, and all the variables

7y-196=0

We move all terms containing y to the left, all other terms to the right

7y=196

y=196/7

y=28

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