4y+4-2(-6y-1)=2(y-3)

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Solution for 4y+4-2(-6y-1)=2(y-3) equation: 



4y+4-2(-6y-1)=2(y-3)

We move all terms to the left:

4y+4-2(-6y-1)-(2(y-3))=0

We multiply parentheses

4y+12y-(2(y-3))+2+4=0



We calculate terms in parentheses: -(2(y-3)), so:

2(y-3)

We multiply parentheses

2y-6

Back to the equation:

-(2y-6)



We add all the numbers together, and all the variables

16y-(2y-6)+6=0

We get rid of parentheses

16y-2y+6+6=0

We add all the numbers together, and all the variables

14y+12=0

We move all terms containing y to the left, all other terms to the right

14y=-12

y=-12/14

y=-6/7

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