4y+4-2(-8y-1)=6(y-2)

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Solution for 4y+4-2(-8y-1)=6(y-2) equation: 



4y+4-2(-8y-1)=6(y-2)

We move all terms to the left:

4y+4-2(-8y-1)-(6(y-2))=0

We multiply parentheses

4y+16y-(6(y-2))+2+4=0



We calculate terms in parentheses: -(6(y-2)), so:

6(y-2)

We multiply parentheses

6y-12

Back to the equation:

-(6y-12)



We add all the numbers together, and all the variables

20y-(6y-12)+6=0

We get rid of parentheses

20y-6y+12+6=0

We add all the numbers together, and all the variables

14y+18=0

We move all terms containing y to the left, all other terms to the right

14y=-18

y=-18/14

y=-1+2/7

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