4y+42=98-10y

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Solution for 4y+42=98-10y equation: 



4y+42=98-10y

We move all terms to the left:

4y+42-(98-10y)=0

We add all the numbers together, and all the variables

4y-(-10y+98)+42=0

We get rid of parentheses

4y+10y-98+42=0

We add all the numbers together, and all the variables

14y-56=0

We move all terms containing y to the left, all other terms to the right

14y=56

y=56/14

y=4

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