4y+48=-3(y-2)

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Solution for 4y+48=-3(y-2) equation:



4y+48=-3(y-2)
We move all terms to the left:
4y+48-(-3(y-2))=0
We calculate terms in parentheses: -(-3(y-2)), so:
-3(y-2)
We multiply parentheses
-3y+6
Back to the equation:
-(-3y+6)
We get rid of parentheses
4y+3y-6+48=0
We add all the numbers together, and all the variables
7y+42=0
We move all terms containing y to the left, all other terms to the right
7y=-42
y=-42/7
y=-6

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