4y+5(7y-3)=9(y-5)

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Solution for 4y+5(7y-3)=9(y-5) equation: 



4y+5(7y-3)=9(y-5)

We move all terms to the left:

4y+5(7y-3)-(9(y-5))=0

We multiply parentheses

4y+35y-(9(y-5))-15=0



We calculate terms in parentheses: -(9(y-5)), so:

9(y-5)

We multiply parentheses

9y-45

Back to the equation:

-(9y-45)



We add all the numbers together, and all the variables

39y-(9y-45)-15=0

We get rid of parentheses

39y-9y+45-15=0

We add all the numbers together, and all the variables

30y+30=0

We move all terms containing y to the left, all other terms to the right

30y=-30

y=-30/30

y=-1

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