4y+5=14+y2

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Solution for 4y+5=14+y2 equation:



4y+5=14+y2
We move all terms to the left:
4y+5-(14+y2)=0
We add all the numbers together, and all the variables
-(+y^2+14)+4y+5=0
We get rid of parentheses
-y^2+4y-14+5=0
We add all the numbers together, and all the variables
-1y^2+4y-9=0
a = -1; b = 4; c = -9;
Δ = b2-4ac
Δ = 42-4·(-1)·(-9)
Δ = -20
Delta is less than zero, so there is no solution for the equation

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