4y+6(2y-4)=40

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Solution for 4y+6(2y-4)=40 equation: 



4y+6(2y-4)=40

We move all terms to the left:

4y+6(2y-4)-(40)=0

We multiply parentheses

4y+12y-24-40=0

We add all the numbers together, and all the variables

16y-64=0

We move all terms containing y to the left, all other terms to the right

16y=64

y=64/16

y=4

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