4y+6-4(-4y-2)=2(y-1)

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Solution for 4y+6-4(-4y-2)=2(y-1) equation: 



4y+6-4(-4y-2)=2(y-1)

We move all terms to the left:

4y+6-4(-4y-2)-(2(y-1))=0

We multiply parentheses

4y+16y-(2(y-1))+8+6=0



We calculate terms in parentheses: -(2(y-1)), so:

2(y-1)

We multiply parentheses

2y-2

Back to the equation:

-(2y-2)



We add all the numbers together, and all the variables

20y-(2y-2)+14=0

We get rid of parentheses

20y-2y+2+14=0

We add all the numbers together, and all the variables

18y+16=0

We move all terms containing y to the left, all other terms to the right

18y=-16

y=-16/18

y=-8/9

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