4y+7(y-3)=34

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Solution for 4y+7(y-3)=34 equation:



4y+7(y-3)=34
We move all terms to the left:
4y+7(y-3)-(34)=0
We multiply parentheses
4y+7y-21-34=0
We add all the numbers together, and all the variables
11y-55=0
We move all terms containing y to the left, all other terms to the right
11y=55
y=55/11
y=5

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