4y+7-y=29(y+3)

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Solution for 4y+7-y=29(y+3) equation: 



4y+7-y=29(y+3)

We move all terms to the left:

4y+7-y-(29(y+3))=0

We add all the numbers together, and all the variables

3y-(29(y+3))+7=0



We calculate terms in parentheses: -(29(y+3)), so:

29(y+3)

We multiply parentheses

29y+87

Back to the equation:

-(29y+87)



We get rid of parentheses

3y-29y-87+7=0

We add all the numbers together, and all the variables

-26y-80=0

We move all terms containing y to the left, all other terms to the right

-26y=80

y=80/-26

y=-3+1/13

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