4y+7y+8(2y-2)=65

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Solution for 4y+7y+8(2y-2)=65 equation: 



4y+7y+8(2y-2)=65

We move all terms to the left:

4y+7y+8(2y-2)-(65)=0

We add all the numbers together, and all the variables

11y+8(2y-2)-65=0

We multiply parentheses

11y+16y-16-65=0

We add all the numbers together, and all the variables

27y-81=0

We move all terms containing y to the left, all other terms to the right

27y=81

y=81/27

y=3

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