4y+y1=7(y-1)

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Solution for 4y+y1=7(y-1) equation: 



4y+y1=7(y-1)

We move all terms to the left:

4y+y1-(7(y-1))=0

We add all the numbers together, and all the variables

5y-(7(y-1))=0



We calculate terms in parentheses: -(7(y-1)), so:

7(y-1)

We multiply parentheses

7y-7

Back to the equation:

-(7y-7)



We get rid of parentheses

5y-7y+7=0

We add all the numbers together, and all the variables

-2y+7=0

We move all terms containing y to the left, all other terms to the right

-2y=-7

y=-7/-2

y=3+1/2

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