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4y+y=4y^2
We move all terms to the left:
4y+y-(4y^2)=0
determiningTheFunctionDomain -4y^2+4y+y=0
We add all the numbers together, and all the variables
-4y^2+5y=0
a = -4; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-4)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-4}=\frac{-10}{-8} =1+1/4 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-4}=\frac{0}{-8} =0 $
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