4y-(2y+1)=3(y+1)-3

Solution for 4y-(2y+1)=3(y+1)-3 equation:

Simplifying
4y + -1(2y + 1) = 3(y + 1) + -3

Reorder the terms:
4y + -1(1 + 2y) = 3(y + 1) + -3
4y + (1 * -1 + 2y * -1) = 3(y + 1) + -3
4y + (-1 + -2y) = 3(y + 1) + -3

Reorder the terms:
-1 + 4y + -2y = 3(y + 1) + -3

Combine like terms: 4y + -2y = 2y
-1 + 2y = 3(y + 1) + -3

Reorder the terms:
-1 + 2y = 3(1 + y) + -3
-1 + 2y = (1 * 3 + y * 3) + -3
-1 + 2y = (3 + 3y) + -3

Reorder the terms:
-1 + 2y = 3 + -3 + 3y

Combine like terms: 3 + -3 = 0
-1 + 2y = 0 + 3y
-1 + 2y = 3y

Solving
-1 + 2y = 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.
-1 + 2y + -3y = 3y + -3y

Combine like terms: 2y + -3y = -1y
-1 + -1y = 3y + -3y

Combine like terms: 3y + -3y = 0
-1 + -1y = 0

Add '1' to each side of the equation.
-1 + 1 + -1y = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1y = 0 + 1
-1y = 0 + 1

Combine like terms: 0 + 1 = 1
-1y = 1

Divide each side by '-1'.
y = -1

Simplifying
y = -1