4y-(2y-9)=2y-(-3y)-3

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Solution for 4y-(2y-9)=2y-(-3y)-3 equation: 



4y-(2y-9)=2y-(-3y)-3

We move all terms to the left:

4y-(2y-9)-(2y-(-3y)-3)=0

We get rid of parentheses

4y-2y-(2y-(-3y)-3)+9=0



We calculate terms in parentheses: -(2y-(-3y)-3), so:

2y-(-3y)-3

We get rid of parentheses

2y+3y-3

We add all the numbers together, and all the variables

5y-3

Back to the equation:

-(5y-3)



We add all the numbers together, and all the variables

2y-(5y-3)+9=0

We get rid of parentheses

2y-5y+3+9=0

We add all the numbers together, and all the variables

-3y+12=0

We move all terms containing y to the left, all other terms to the right

-3y=-12

y=-12/-3

y=+4

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