4y-(3+y);y=2=

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Solution for 4y-(3+y);y=2= equation: 



4y-(3+y)y=2=

We move all terms to the left:

4y-(3+y)y-(2)=0

We add all the numbers together, and all the variables

4y-(y+3)y-2=0

We multiply parentheses

-y^2+4y-3y-2=0

We add all the numbers together, and all the variables

-1y^2+y-2=0

a = -1; b = 1; c = -2;
Δ = b2-4ac
Δ = 12-4·(-1)·(-2)
Δ = -7
Delta is less than zero, so there is no solution for the equation

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