4y-(3+y)y=5

Solution for 4y-(3+y)y=5 equation:

Simplifying
4y + -1(3 + y) * y = 5

Reorder the terms for easier multiplication:
4y + -1y(3 + y) = 5
4y + (3 * -1y + y * -1y) = 5
4y + (-3y + -1y2) = 5

Combine like terms: 4y + -3y = 1y
1y + -1y2 = 5

Solving
1y + -1y2 = 5

Solving for variable 'y'.

Reorder the terms:
-5 + 1y + -1y2 = 5 + -5

Combine like terms: 5 + -5 = 0
-5 + 1y + -1y2 = 0

Begin completing the square.  Divide all terms by
-1 the coefficient of the squared term: 

Divide each side by '-1'.
5 + -1y + y2 = 0

Move the constant term to the right:

Add '-5' to each side of the equation.
5 + -1y + -5 + y2 = 0 + -5

Reorder the terms:
5 + -5 + -1y + y2 = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -1y + y2 = 0 + -5
-1y + y2 = 0 + -5

Combine like terms: 0 + -5 = -5
-1y + y2 = -5

The y term is -1y.  Take half its coefficient (-0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
-1y + 0.25 + y2 = -5 + 0.25

Reorder the terms:
0.25 + -1y + y2 = -5 + 0.25

Combine like terms: -5 + 0.25 = -4.75
0.25 + -1y + y2 = -4.75

Factor a perfect square on the left side:
(y + -0.5)(y + -0.5) = -4.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.