4y-1+2(3-2y)=5

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Solution for 4y-1+2(3-2y)=5 equation:



4y-1+2(3-2y)=5
We move all terms to the left:
4y-1+2(3-2y)-(5)=0
We add all the numbers together, and all the variables
4y+2(-2y+3)-1-5=0
We add all the numbers together, and all the variables
4y+2(-2y+3)-6=0
We multiply parentheses
4y-4y+6-6=0
We add all the numbers together, and all the variables
=0
y=0/1
y=0

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