4y-10+y+50=7y+40-5y

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Solution for 4y-10+y+50=7y+40-5y equation: 



4y-10+y+50=7y+40-5y

We move all terms to the left:

4y-10+y+50-(7y+40-5y)=0

We add all the numbers together, and all the variables

4y+y-(2y+40)-10+50=0

We add all the numbers together, and all the variables

5y-(2y+40)+40=0

We get rid of parentheses

5y-2y-40+40=0

We add all the numbers together, and all the variables

3y=0

y=0/3

y=0

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