4y-109=9y/8+6

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Solution for 4y-109=9y/8+6 equation: 



4y-109=9y/8+6

We move all terms to the left:

4y-109-(9y/8+6)=0

We get rid of parentheses

4y-9y/8-6-109=0

We multiply all the terms by the denominator


4y*8-9y-6*8-109*8=0

We add all the numbers together, and all the variables

-9y+4y*8-920=0

Wy multiply elements

-9y+32y-920=0

We add all the numbers together, and all the variables

23y-920=0

We move all terms containing y to the left, all other terms to the right

23y=920

y=920/23

y=40

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