4y-10=12+2(y+8)

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Solution for 4y-10=12+2(y+8) equation: 



4y-10=12+2(y+8)

We move all terms to the left:

4y-10-(12+2(y+8))=0



We calculate terms in parentheses: -(12+2(y+8)), so:

12+2(y+8)

determiningTheFunctionDomain
2(y+8)+12

We multiply parentheses

2y+16+12

We add all the numbers together, and all the variables

2y+28

Back to the equation:

-(2y+28)



We get rid of parentheses

4y-2y-28-10=0

We add all the numbers together, and all the variables

2y-38=0

We move all terms containing y to the left, all other terms to the right

2y=38

y=38/2

y=19

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