4y-12(2)=20

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Solution for 4y-12(2)=20 equation:



4y-12(2)=20
We move all terms to the left:
4y-12(2)-(20)=0
We add all the numbers together, and all the variables
4y-142=0
We move all terms containing y to the left, all other terms to the right
4y=142
y=142/4
y=35+1/2

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