4y-12=-8(y-3)

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Solution for 4y-12=-8(y-3) equation: 



4y-12=-8(y-3)

We move all terms to the left:

4y-12-(-8(y-3))=0



We calculate terms in parentheses: -(-8(y-3)), so:

-8(y-3)

We multiply parentheses

-8y+24

Back to the equation:

-(-8y+24)



We get rid of parentheses

4y+8y-24-12=0

We add all the numbers together, and all the variables

12y-36=0

We move all terms containing y to the left, all other terms to the right

12y=36

y=36/12

y=3

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