4y-2(1+y)=4y-2+2y

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Solution for 4y-2(1+y)=4y-2+2y equation: 



4y-2(1+y)=4y-2+2y

We move all terms to the left:

4y-2(1+y)-(4y-2+2y)=0

We add all the numbers together, and all the variables

4y-2(y+1)-(6y-2)=0

We multiply parentheses

4y-2y-(6y-2)-2=0

We get rid of parentheses

4y-2y-6y+2-2=0

We add all the numbers together, and all the variables

-4y=0

y=0/-4

y=0

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