4y-2(3y+3)=-3-4(-5-y)

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Solution for 4y-2(3y+3)=-3-4(-5-y) equation: 



4y-2(3y+3)=-3-4(-5-y)

We move all terms to the left:

4y-2(3y+3)-(-3-4(-5-y))=0

We add all the numbers together, and all the variables

4y-2(3y+3)-(-3-4(-1y-5))=0

We multiply parentheses

4y-6y-(-3-4(-1y-5))-6=0



We calculate terms in parentheses: -(-3-4(-1y-5)), so:

-3-4(-1y-5)

determiningTheFunctionDomain
-4(-1y-5)-3

We multiply parentheses

4y+20-3

We add all the numbers together, and all the variables

4y+17

Back to the equation:

-(4y+17)



We add all the numbers together, and all the variables

-2y-(4y+17)-6=0

We get rid of parentheses

-2y-4y-17-6=0

We add all the numbers together, and all the variables

-6y-23=0

We move all terms containing y to the left, all other terms to the right

-6y=23

y=23/-6

y=-3+5/6

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