4y-2(4y+2)=-5-4(1-y)

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Solution for 4y-2(4y+2)=-5-4(1-y) equation: 



4y-2(4y+2)=-5-4(1-y)

We move all terms to the left:

4y-2(4y+2)-(-5-4(1-y))=0

We add all the numbers together, and all the variables

4y-2(4y+2)-(-5-4(-1y+1))=0

We multiply parentheses

4y-8y-(-5-4(-1y+1))-4=0



We calculate terms in parentheses: -(-5-4(-1y+1)), so:

-5-4(-1y+1)

determiningTheFunctionDomain
-4(-1y+1)-5

We multiply parentheses

4y-4-5

We add all the numbers together, and all the variables

4y-9

Back to the equation:

-(4y-9)



We add all the numbers together, and all the variables

-4y-(4y-9)-4=0

We get rid of parentheses

-4y-4y+9-4=0

We add all the numbers together, and all the variables

-8y+5=0

We move all terms containing y to the left, all other terms to the right

-8y=-5

y=-5/-8

y=5/8

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