4y-2(5y+1)=16+3(4y-10)

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Solution for 4y-2(5y+1)=16+3(4y-10) equation:


Simplifying
4y + -2(5y + 1) = 16 + 3(4y + -10)

Reorder the terms:
4y + -2(1 + 5y) = 16 + 3(4y + -10)
4y + (1 * -2 + 5y * -2) = 16 + 3(4y + -10)
4y + (-2 + -10y) = 16 + 3(4y + -10)

Reorder the terms:
-2 + 4y + -10y = 16 + 3(4y + -10)

Combine like terms: 4y + -10y = -6y
-2 + -6y = 16 + 3(4y + -10)

Reorder the terms:
-2 + -6y = 16 + 3(-10 + 4y)
-2 + -6y = 16 + (-10 * 3 + 4y * 3)
-2 + -6y = 16 + (-30 + 12y)

Combine like terms: 16 + -30 = -14
-2 + -6y = -14 + 12y

Solving
-2 + -6y = -14 + 12y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-12y' to each side of the equation.
-2 + -6y + -12y = -14 + 12y + -12y

Combine like terms: -6y + -12y = -18y
-2 + -18y = -14 + 12y + -12y

Combine like terms: 12y + -12y = 0
-2 + -18y = -14 + 0
-2 + -18y = -14

Add '2' to each side of the equation.
-2 + 2 + -18y = -14 + 2

Combine like terms: -2 + 2 = 0
0 + -18y = -14 + 2
-18y = -14 + 2

Combine like terms: -14 + 2 = -12
-18y = -12

Divide each side by '-18'.
y = 0.6666666667

Simplifying
y = 0.6666666667

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