4y-2(6+y)=8y+(-32)

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Solution for 4y-2(6+y)=8y+(-32) equation: 



4y-2(6+y)=8y+(-32)

We move all terms to the left:

4y-2(6+y)-(8y+(-32))=0

We add all the numbers together, and all the variables

4y-2(y+6)-(8y+(-32))=0

We multiply parentheses

4y-2y-(8y+(-32))-12=0



We calculate terms in parentheses: -(8y+(-32)), so:

8y+(-32)

We add all the numbers together, and all the variables

8y-32

Back to the equation:

-(8y-32)



We add all the numbers together, and all the variables

2y-(8y-32)-12=0

We get rid of parentheses

2y-8y+32-12=0

We add all the numbers together, and all the variables

-6y+20=0

We move all terms containing y to the left, all other terms to the right

-6y=-20

y=-20/-6

y=3+1/3

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