4y-2(6-y)=6(3y+2)

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Solution for 4y-2(6-y)=6(3y+2) equation: 



4y-2(6-y)=6(3y+2)

We move all terms to the left:

4y-2(6-y)-(6(3y+2))=0

We add all the numbers together, and all the variables

4y-2(-1y+6)-(6(3y+2))=0

We multiply parentheses

4y+2y-(6(3y+2))-12=0



We calculate terms in parentheses: -(6(3y+2)), so:

6(3y+2)

We multiply parentheses

18y+12

Back to the equation:

-(18y+12)



We add all the numbers together, and all the variables

6y-(18y+12)-12=0

We get rid of parentheses

6y-18y-12-12=0

We add all the numbers together, and all the variables

-12y-24=0

We move all terms containing y to the left, all other terms to the right

-12y=24

y=24/-12

y=-2

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