4y-2(y+3)=-2(2-y)

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Solution for 4y-2(y+3)=-2(2-y) equation: 



4y-2(y+3)=-2(2-y)

We move all terms to the left:

4y-2(y+3)-(-2(2-y))=0

We add all the numbers together, and all the variables

4y-2(y+3)-(-2(-1y+2))=0

We multiply parentheses

4y-2y-(-2(-1y+2))-6=0



We calculate terms in parentheses: -(-2(-1y+2)), so:

-2(-1y+2)

We multiply parentheses

2y-4

Back to the equation:

-(2y-4)



We add all the numbers together, and all the variables

2y-(2y-4)-6=0

We get rid of parentheses

2y-2y+4-6=0

We add all the numbers together, and all the variables

-2!=0

There is no solution for this equation

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