4y-2+2(5y+1)=-2(y+6)

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Solution for 4y-2+2(5y+1)=-2(y+6) equation: 



4y-2+2(5y+1)=-2(y+6)

We move all terms to the left:

4y-2+2(5y+1)-(-2(y+6))=0

We multiply parentheses

4y+10y-(-2(y+6))+2-2=0



We calculate terms in parentheses: -(-2(y+6)), so:

-2(y+6)

We multiply parentheses

-2y-12

Back to the equation:

-(-2y-12)



We add all the numbers together, and all the variables

14y-(-2y-12)=0

We get rid of parentheses

14y+2y+12=0

We add all the numbers together, and all the variables

16y+12=0

We move all terms containing y to the left, all other terms to the right

16y=-12

y=-12/16

y=-3/4

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