4y-2+2(6y+1)=-2(y+5)

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Solution for 4y-2+2(6y+1)=-2(y+5) equation: 



4y-2+2(6y+1)=-2(y+5)

We move all terms to the left:

4y-2+2(6y+1)-(-2(y+5))=0

We multiply parentheses

4y+12y-(-2(y+5))+2-2=0



We calculate terms in parentheses: -(-2(y+5)), so:

-2(y+5)

We multiply parentheses

-2y-10

Back to the equation:

-(-2y-10)



We add all the numbers together, and all the variables

16y-(-2y-10)=0

We get rid of parentheses

16y+2y+10=0

We add all the numbers together, and all the variables

18y+10=0

We move all terms containing y to the left, all other terms to the right

18y=-10

y=-10/18

y=-5/9

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