4y-2+y+32=7y+30-4y

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Solution for 4y-2+y+32=7y+30-4y equation: 



4y-2+y+32=7y+30-4y

We move all terms to the left:

4y-2+y+32-(7y+30-4y)=0

We add all the numbers together, and all the variables

4y+y-(3y+30)-2+32=0

We add all the numbers together, and all the variables

5y-(3y+30)+30=0

We get rid of parentheses

5y-3y-30+30=0

We add all the numbers together, and all the variables

2y=0

y=0/2

y=0

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