4y-2+y+33=7y+40-5y

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Solution for 4y-2+y+33=7y+40-5y equation:


4y-2+y+33=7y+40-5y

We simplify the equation to the form, which is simple to understand 
4y-2+y+33=7y+40-5y

We move all terms containing y to the left and all other terms to the right. 
+4y+1y-7y+5y=+40+2-33

We simplify left and right side of the equation. 
+3y=+9

We divide both sides of the equation by 3 to get y. 
y=3

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