4y-3(2-8)=4(-2y)+50

Solution for 4y-3(2-8)=4(-2y)+50 equation:

4y-3(2-8)=4(-2y)+50

We move all terms to the left:

4y-3(2-8)-(4(-2y)+50)=0

We add all the numbers together, and all the variables

4y-(4(-2y)+50)-3(-6)=0

We add all the numbers together, and all the variables

4y-(4(-2y)+50)+18=0


We calculate terms in parentheses: -(4(-2y)+50), so:

4(-2y)+50

We multiply parentheses

-8y+50

Back to the equation:

-(-8y+50)


We get rid of parentheses

4y+8y-50+18=0

We add all the numbers together, and all the variables

12y-32=0

We move all terms containing y to the left, all other terms to the right

12y=32

y=32/12

y=2+2/3