4y-3(y-2)=2(3y-2)

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Solution for 4y-3(y-2)=2(3y-2) equation: 



4y-3(y-2)=2(3y-2)

We move all terms to the left:

4y-3(y-2)-(2(3y-2))=0

We multiply parentheses

4y-3y-(2(3y-2))+6=0



We calculate terms in parentheses: -(2(3y-2)), so:

2(3y-2)

We multiply parentheses

6y-4

Back to the equation:

-(6y-4)



We add all the numbers together, and all the variables

y-(6y-4)+6=0

We get rid of parentheses

y-6y+4+6=0

We add all the numbers together, and all the variables

-5y+10=0

We move all terms containing y to the left, all other terms to the right

-5y=-10

y=-10/-5

y=+2

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