4y-3(y-3)+1=6

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Solution for 4y-3(y-3)+1=6 equation: 


Simplifying
4y + -3(y + -3) + 1 = 6

Reorder the terms:
4y + -3(-3 + y) + 1 = 6
4y + (-3 * -3 + y * -3) + 1 = 6
4y + (9 + -3y) + 1 = 6

Reorder the terms:
9 + 1 + 4y + -3y = 6

Combine like terms: 9 + 1 = 10
10 + 4y + -3y = 6

Combine like terms: 4y + -3y = 1y
10 + 1y = 6

Solving
10 + 1y = 6

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + 1y = 6 + -10

Combine like terms: 10 + -10 = 0
0 + 1y = 6 + -10
1y = 6 + -10

Combine like terms: 6 + -10 = -4
1y = -4

Divide each side by '1'.
y = -4

Simplifying
y = -4

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