4y-3(y-4)+1=5

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Solution for 4y-3(y-4)+1=5 equation: 


Simplifying
4y + -3(y + -4) + 1 = 5

Reorder the terms:
4y + -3(-4 + y) + 1 = 5
4y + (-4 * -3 + y * -3) + 1 = 5
4y + (12 + -3y) + 1 = 5

Reorder the terms:
12 + 1 + 4y + -3y = 5

Combine like terms: 12 + 1 = 13
13 + 4y + -3y = 5

Combine like terms: 4y + -3y = 1y
13 + 1y = 5

Solving
13 + 1y = 5

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-13' to each side of the equation.
13 + -13 + 1y = 5 + -13

Combine like terms: 13 + -13 = 0
0 + 1y = 5 + -13
1y = 5 + -13

Combine like terms: 5 + -13 = -8
1y = -8

Divide each side by '1'.
y = -8

Simplifying
y = -8

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