4y-3*(20-y)=6y-7*(11-y)

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Solution for 4y-3*(20-y)=6y-7*(11-y) equation: 



4y-3(20-y)=6y-7(11-y)

We move all terms to the left:

4y-3(20-y)-(6y-7(11-y))=0

We add all the numbers together, and all the variables

4y-3(-1y+20)-(6y-7(-1y+11))=0

We multiply parentheses

4y+3y-(6y-7(-1y+11))-60=0



We calculate terms in parentheses: -(6y-7(-1y+11)), so:

6y-7(-1y+11)

We multiply parentheses

6y+7y-77

We add all the numbers together, and all the variables

13y-77

Back to the equation:

-(13y-77)



We add all the numbers together, and all the variables

7y-(13y-77)-60=0

We get rid of parentheses

7y-13y+77-60=0

We add all the numbers together, and all the variables

-6y+17=0

We move all terms containing y to the left, all other terms to the right

-6y=-17

y=-17/-6

y=2+5/6

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