4y-3+2(3y+1)=-2(y+2)

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Solution for 4y-3+2(3y+1)=-2(y+2) equation:


Simplifying
4y + -3 + 2(3y + 1) = -2(y + 2)

Reorder the terms:
4y + -3 + 2(1 + 3y) = -2(y + 2)
4y + -3 + (1 * 2 + 3y * 2) = -2(y + 2)
4y + -3 + (2 + 6y) = -2(y + 2)

Reorder the terms:
-3 + 2 + 4y + 6y = -2(y + 2)

Combine like terms: -3 + 2 = -1
-1 + 4y + 6y = -2(y + 2)

Combine like terms: 4y + 6y = 10y
-1 + 10y = -2(y + 2)

Reorder the terms:
-1 + 10y = -2(2 + y)
-1 + 10y = (2 * -2 + y * -2)
-1 + 10y = (-4 + -2y)

Solving
-1 + 10y = -4 + -2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '2y' to each side of the equation.
-1 + 10y + 2y = -4 + -2y + 2y

Combine like terms: 10y + 2y = 12y
-1 + 12y = -4 + -2y + 2y

Combine like terms: -2y + 2y = 0
-1 + 12y = -4 + 0
-1 + 12y = -4

Add '1' to each side of the equation.
-1 + 1 + 12y = -4 + 1

Combine like terms: -1 + 1 = 0
0 + 12y = -4 + 1
12y = -4 + 1

Combine like terms: -4 + 1 = -3
12y = -3

Divide each side by '12'.
y = -0.25

Simplifying
y = -0.25

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