4y-3.5=2y+3(y+0.2);y=-1.5

Solution for 4y-3.5=2y+3(y+0.2);y=-1.5 equation:

4y-3.5=2y+3(y+0.2)y=-1.5

We move all terms to the left:

4y-3.5-(2y+3(y+0.2)y)=0


We calculate terms in parentheses: -(2y+3(y+0.2)y), so:

2y+3(y+0.2)y

We multiply parentheses

3y^2+2y+0.6y

We add all the numbers together, and all the variables

3y^2+2.6y

Back to the equation:

-(3y^2+2.6y)


We get rid of parentheses

-3y^2+4y-2.6y-3.5=0

We add all the numbers together, and all the variables

-3y^2+1.4y-3.5=0

a = -3; b = 1.4; c = -3.5;
Δ = b2-4ac
Δ = 1.42-4·(-3)·(-3.5)
Δ = -40.04
Delta is less than zero, so there is no solution for the equation