4y-3=1/3(12y-9)-8y

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Solution for 4y-3=1/3(12y-9)-8y equation: 



4y-3=1/3(12y-9)-8y

We move all terms to the left:

4y-3-(1/3(12y-9)-8y)=0



Domain of the equation: 3(12y-9)-8y)!=0

y∈R



We multiply all the terms by the denominator


4y*3(12y-9)-8y)-(1-3*3(12y-9)-8y)=0

Wy multiply elements

12y^2(1-8y)-(1-9y(1-8y)=0



We calculate terms in parentheses: -(1-9y(1-8y), so:

1-9y(1-8y

determiningTheFunctionDomain
-9y(1-8y+1

Back to the equation:

-(-9y(1-8y+1)



We add all the numbers together, and all the variables

12y^2(-8y+1)-(-9y(-8y+2)=0



We calculate terms in parentheses: -(-9y(-8y+2), so:

-9y(-8y+2





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-9y(-8y+2





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-9y(-8y+2





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-9y(-8y+2





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-9y(-8y+2





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-9y(-8y+2





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-9y(-8y+2





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