4y-3=4(y+1)

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Solution for 4y-3=4(y+1) equation: 



4y-3=4(y+1)

We move all terms to the left:

4y-3-(4(y+1))=0



We calculate terms in parentheses: -(4(y+1)), so:

4(y+1)

We multiply parentheses

4y+4

Back to the equation:

-(4y+4)



We get rid of parentheses

4y-4y-4-3=0

We add all the numbers together, and all the variables

-7!=0

There is no solution for this equation

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