4y-3=4(y+1)

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Solution for 4y-3=4(y+1) equation:



4y-3=4(y+1)
We move all terms to the left:
4y-3-(4(y+1))=0
We calculate terms in parentheses: -(4(y+1)), so:
4(y+1)
We multiply parentheses
4y+4
Back to the equation:
-(4y+4)
We get rid of parentheses
4y-4y-4-3=0
We add all the numbers together, and all the variables
-7!=0
There is no solution for this equation

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