4y-4(3y+1)=-4-2(-3-y)

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Solution for 4y-4(3y+1)=-4-2(-3-y) equation: 



4y-4(3y+1)=-4-2(-3-y)

We move all terms to the left:

4y-4(3y+1)-(-4-2(-3-y))=0

We add all the numbers together, and all the variables

4y-4(3y+1)-(-4-2(-1y-3))=0

We multiply parentheses

4y-12y-(-4-2(-1y-3))-4=0



We calculate terms in parentheses: -(-4-2(-1y-3)), so:

-4-2(-1y-3)

determiningTheFunctionDomain
-2(-1y-3)-4

We multiply parentheses

2y+6-4

We add all the numbers together, and all the variables

2y+2

Back to the equation:

-(2y+2)



We add all the numbers together, and all the variables

-8y-(2y+2)-4=0

We get rid of parentheses

-8y-2y-2-4=0

We add all the numbers together, and all the variables

-10y-6=0

We move all terms containing y to the left, all other terms to the right

-10y=6

y=6/-10

y=-3/5

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