4y-4(y+3)=3(y+1)

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Solution for 4y-4(y+3)=3(y+1) equation:


Simplifying
4y + -4(y + 3) = 3(y + 1)

Reorder the terms:
4y + -4(3 + y) = 3(y + 1)
4y + (3 * -4 + y * -4) = 3(y + 1)
4y + (-12 + -4y) = 3(y + 1)

Reorder the terms:
-12 + 4y + -4y = 3(y + 1)

Combine like terms: 4y + -4y = 0
-12 + 0 = 3(y + 1)
-12 = 3(y + 1)

Reorder the terms:
-12 = 3(1 + y)
-12 = (1 * 3 + y * 3)
-12 = (3 + 3y)

Solving
-12 = 3 + 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.
-12 + -3y = 3 + 3y + -3y

Combine like terms: 3y + -3y = 0
-12 + -3y = 3 + 0
-12 + -3y = 3

Add '12' to each side of the equation.
-12 + 12 + -3y = 3 + 12

Combine like terms: -12 + 12 = 0
0 + -3y = 3 + 12
-3y = 3 + 12

Combine like terms: 3 + 12 = 15
-3y = 15

Divide each side by '-3'.
y = -5

Simplifying
y = -5

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