4y-4+2(2y+5)=-2(y+5)

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Solution for 4y-4+2(2y+5)=-2(y+5) equation: 



4y-4+2(2y+5)=-2(y+5)

We move all terms to the left:

4y-4+2(2y+5)-(-2(y+5))=0

We multiply parentheses

4y+4y-(-2(y+5))+10-4=0



We calculate terms in parentheses: -(-2(y+5)), so:

-2(y+5)

We multiply parentheses

-2y-10

Back to the equation:

-(-2y-10)



We add all the numbers together, and all the variables

8y-(-2y-10)+6=0

We get rid of parentheses

8y+2y+10+6=0

We add all the numbers together, and all the variables

10y+16=0

We move all terms containing y to the left, all other terms to the right

10y=-16

y=-16/10

y=-1+3/5

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